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Answer by Andreas Thom for Hochschild/cyclic homology of von Neumann...

There is important work by Alain Connes and Dimitri Shlyakhtenko (see $L^2$-homology for von Neumann algebras (MSN)). They come up with a definition of $\ell^2$-homology for finite von Neumann algebras...

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Answer by Claude Schochet for Hochschild/cyclic homology of von Neumann...

The question is not well-posed. There are various versions of cyclic theory (for instance) which differ according to continuity conditions that are assumed. In Connes' original IHES papers he deals...

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Answer by Yemon Choi for Hochschild/cyclic homology of von Neumann algebras:...

This is in response to Dmitri's remark. The reason I didn't bring up Sinclair & Smith's book (which is where I first started trying to learn Hochschild cohomology) is that it deals with continuous...

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Answer by Dmitri Pavlov for Hochschild/cyclic homology of von Neumann...

I am surprised that nobody mentioned the book by Sinclair and Smith “Hochschild Cohomology of von Neumann algebras” so far.If I remember it correctly, they claim that nobody knows whether there is a...

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Answer by Yemon Choi for Hochschild/cyclic homology of von Neumann algebras:...

Some further thoughts: the most striking results I know of on "purely algebraic cyclic/Hochschild homology" are due to Wodzicki, see e.g.Wodzicki, Mariusz, Homological properties of rings of...

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Answer by Yemon Choi for Hochschild/cyclic homology of von Neumann algebras:...

As someone who works on the continuous (bounded) cohomology of Banach algebras: I think the quote is a way of saying "we don't really know". There are certainly questions which start off with extra...

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Answer by GMRA for Hochschild/cyclic homology of von Neumann algebras: useless?

I am certainly not an expert, but I guess that when people say There's also analysis in von Neumann algebras, so I wouldn't expect an algebraic invariant like Hochschild or cyclic homology to tell you...

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Hochschild/cyclic homology of von Neumann algebras: useless?

Hochschild homology gives invariants of (unital) $k$-algebras for $k$ a unital, commutative ring. If we let our algebra $A$ be the group ring $k[G]$ for $G$ a finite group, we get group homology. There...

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